Math, asked by jafarali3612, 4 months ago

P(x)=x4_5x+6,g(x)=2-x2​

Answers

Answered by sumit11g
1

Step-by-step explanation:

Answer:

Quotient= (-x^2-2)(−x

2

−2) and Remainder= (-5x+8)(−5x+8)

Step-by-step explanation:

Given : p(x)=x^4-5x+6p(x)=x

4

−5x+6 and g(x) = 2-x^2g(x)=2−x

2

To divide the p(x) by g(x)

We know, Dividend = Divisor × quotient + remainder

p(x)= Dividend , g(x)=Divisor

\frac{x^4-5x+6}{2-x^2}

2−x

2

x

4

−5x+6

= quotient + remainder

Solve by long division we get,

{\frac{x^4-5x+6}{2-x^2}=(-x^2-2)+(-5x+8)

By dividing we get,

Quotient= (-x^2-2)(−x

2

−2) and Remainder= (-5x+8)(−5x+8)

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