P(x)=x4_5x+6,g(x)=2-x2
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Step-by-step explanation:
Answer:
Quotient= (-x^2-2)(−x
2
−2) and Remainder= (-5x+8)(−5x+8)
Step-by-step explanation:
Given : p(x)=x^4-5x+6p(x)=x
4
−5x+6 and g(x) = 2-x^2g(x)=2−x
2
To divide the p(x) by g(x)
We know, Dividend = Divisor × quotient + remainder
p(x)= Dividend , g(x)=Divisor
\frac{x^4-5x+6}{2-x^2}
2−x
2
x
4
−5x+6
= quotient + remainder
Solve by long division we get,
{\frac{x^4-5x+6}{2-x^2}=(-x^2-2)+(-5x+8)
By dividing we get,
Quotient= (-x^2-2)(−x
2
−2) and Remainder= (-5x+8)(−5x+8)
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