p(x)=xsquare_3x+2 find p(0),p(1),p(2) for each of the following polinomials
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Answered by
3
Heya !!!
P(X) = X² - 3X + 2
P(0) = (0)² - 3 × 0 + 2 = 0 - 0 + 2 = 2
P(1) = (1)² - 3 × 1 + 2 = 1 - 3 + 2 = 3-3 = 0
P(2) = (2)² - 3 × 2 + 2 = 4 - 6 + 2 = 6 -6 = 0
Hence,
P(0) = 2 , P(1) = 0 and P(2) = 0.
★ HOPE IT WILL HELP YOU ★
P(X) = X² - 3X + 2
P(0) = (0)² - 3 × 0 + 2 = 0 - 0 + 2 = 2
P(1) = (1)² - 3 × 1 + 2 = 1 - 3 + 2 = 3-3 = 0
P(2) = (2)² - 3 × 2 + 2 = 4 - 6 + 2 = 6 -6 = 0
Hence,
P(0) = 2 , P(1) = 0 and P(2) = 0.
★ HOPE IT WILL HELP YOU ★
VijayaLaxmiMehra1:
:-)
Answered by
3
Hey!!
p (x) = x^2 - 3x + 2
p (0) = 0^2 - 3 × 0 + 2 = 2
p ( 1 ) = 1^2 - 3 × 1 + 2 = 1 - 3 + 2 = 0
p ( 2 ) = 2^2 - 3 × 2 + 2 = 4 - 6 + 2 = 0
Hence p ( 0 ) = 2, p ( 1 ) = 0 and p ( 2 ) = 0
Hope it will helps you:-)
p (x) = x^2 - 3x + 2
p (0) = 0^2 - 3 × 0 + 2 = 2
p ( 1 ) = 1^2 - 3 × 1 + 2 = 1 - 3 + 2 = 0
p ( 2 ) = 2^2 - 3 × 2 + 2 = 4 - 6 + 2 = 0
Hence p ( 0 ) = 2, p ( 1 ) = 0 and p ( 2 ) = 0
Hope it will helps you:-)
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