Question

p(x) = xsquare - x+3, thеn p (7root7) = ?
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Answer 1

$\bf \underline{answer : } \\ \\ \sf \implies \:p(x) = {x}^{2} - x + 3 \\ \\ \sf \implies \:p(7 \sqrt{7} ) = {(7 \sqrt{7} })^{2} - (7 \sqrt{7} ) + 3 \\ \\ \sf \implies \:p(7 \sqrt{7} ) = 49 \times 7 - 7 \sqrt{7} + 3 \\ \\ \sf \implies \:p(7 \sqrt{7} ) = 343 - 7 \sqrt{7} + 3 \\ \\ \sf \implies \:p(7 \sqrt{7} ) = 346 - 7 \sqrt{7}$

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