Math, asked by vivek14042001, 17 days ago

P=x+y+z/2 and (p-x):(p-y):(p-z)= 3:5:7 find x:y:z

Answers

Answered by anushrutipandey040
0

Answer:

P = x+y+z ÷2

(P-x)=3 [ Putting the value of P]

=>-x+y+z=6-------->(I)

(P-y)=5

=>x-y+z=10-------(II)

(P-z)=7

=>x+y-z=14-------(III)

(I)+(II)+(III),

x+y+z=6+10+14=>30

P = x+y+z ÷2

=>P=30÷2=>15

(P-x)=3

=>x=12

(P-y)=5

=>y=10

(P-z)=7

=>z=8

So, x:y:z=12:10:8

=>6:5:4

I hope it will help you .

Plz mark me as brainliest

Step-by-step explanation:

Similar questions