Question

p(x)= Y3-6Y2+6Y+1, g(x)= Y-1

Answer 1

y-1 )y3 -6y2 + 6y + 1 ( y2 -5y + 1
.......y3 - y2 ( add (ve-) for these terms ) => y3 ÷ y = y2
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.....0 + 5y2 + 6y => -5y2 ÷ y = -5y2
.....0 - 5y2 - 5y ( add( ve-) for these terms)
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...............0 + y +1
..........( -)0 + y - 1
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.................0...............
r(x) =o
q(x)= y2 - 5y + 1