Question

p=x²-36÷x²-49 and x+6÷x+7 then find p/q

Answer 1

Step-by-step explanation:

value of p= x sq-6 sq. / x sq - 7 sq.

=(x+6)(x-6)/(x+7)/(x-7)=(x+6)(x-6)

value of q=x +6/x-6

therefore, p/q=(x+6)(x-6)/(x+7)/(x-7)×(x+7)/x+6

=(x-6)/(x-7)

hope this helps u stay blessed dear

Answer 2

Answer:

p/q = x - 6/x - 7

Step-by-step explanation:

In think, you have not mentioned q.

So, I think it may be,

p = x² - 36 / x² - 49

q = x + 6 / x +7

Now, dividing p and q, we get :

p/q = [{x² - (6)² / x² - (7)²} ÷ {x + 6 / x+ 7}]

p/q = [{(x - 6)(x + 6) / (x - 7)( x +7)} ÷ {x + 6 / x+ 7}]

p/q = x - 6/x - 7 [ answer ]