Question

p(y)=2+y+2ysquare_ycube find p(0),p(1),p(2) for each of the following polynomials

Answer 1

I hope this answer would be helpful for you

Answer 2

p(y)= 2+y+2y^2-y^3
p(0)= 2+0+0^2-0^3
p(0)=2
p(1)=2+1+2(1^2)-1^3
p(1)=4
p(2)= 2+2+2(2)^2-(2)^3
p(2)= 4+8-8
p(2)=4
p(0)=2, p(1)=4,p(2)=4 is answer