p(y)= 2y² - 2y + 5
Find = p(0), p(1) , p(-1)
Answers
Answer:
p(0)=2×(0)^2-2×0+5
=0-0+5
=5
p(1)=2×(1)^2-2(1)+5
=2-2+5
=5
p(-1)=2×(-1)^2-2×(-1)+5
=2+2+5
=9
Hope this helpful to you
Answer: Given: p(y) = 2y²– 2y +5
Step 1 : p(0) = 2(0)² - 2(0) +5
= 0-0+5
p(0) = 5
Step 2 : p(1) = 2(1)² - 2(1) +5
= 2-2+5
p(1) = 5
step 3: p(-1) = 2(-1) ²- 2(-1) +5
= 2+2+5
p(-1) = 9
Explanation :
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