Question

p(y) = 2y³ + 4y² - 8 at y = -1.

Answer 1

Answer:

$2( { - 1}^{3} ) + 4( { - 1}^{2} ) - 8 \\ 2( - 1) + 4(1) - 8 \\ - 2 + 4 - 8 \\ 4 - 10 \\ - 6$

Step-by-step explanation:

mark me as brainlist

Answer 2

Answer: -6

Step-by-step explanation:

❍ Given :-

• y = - 1

❍ Solution :-

Equation⇝ 2y³ + 4y² - 8

Putting y = -1

$\sf →2{(-1)}^3 + 4{(1)}^2 - 8$

$\sf →2(-1) + 4(1) - 8$

$\sf →-2 + 4 - 8$

$\sf →-6$

Hence, P(y) = 2y³ + 4y² - 8 at y = -1 is -6.