Question

P{y}=4+3y-y square+5ycube. Find the the valu off p(2)

Answer 1

Explanation:

it is given that value of y is 2

at the place of y substitute 2:

p(y)= 4+3y-y²+5y³

p(2)=4+3(2)-(2)²+5(2)³

= 4+6-4+5(8)

=(4 and -4 cancels off) 6+40

=46

therefore, p(2)=46