p[y]=5y-1 find there values
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5y-1=0
5y=0+1
y=1/5
y=0.2
Therefore p(y)=0.2 or 1/5
5y=0+1
y=1/5
y=0.2
Therefore p(y)=0.2 or 1/5
Answered by
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5y-1=0
5y=0+1
y=1/5
y=0.2 p(y)=0.2 or 1/5
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