p(y) = 5y-2 का शून्यक ज्ञात कीजिए।
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Given : p(y) = 5y-2
To Find : शून्यक
Zero
Solution:
p(y) = 5y-2
To Find zero
p(y) = 0
=> 5y-2 = 0
=> y = 2/5
p(y) = 5y-2 का शून्यक = 2/5
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प्रश्न :- p(y) = 5y-2 का शून्यक ज्ञात कीजिए।
उतर :-
p(y) को जीरो के बराबर रखने पर,
→ p(y) = 0
→ 5y - 2 = 0
→ 5y = 2
दोनों तरफ 5 से भाग देने पर,,
→ y = (2/5)
इसलिए p(y) का शून्यक (2/5) होगा l
यह भी देखें :-
JEE mains Question :-
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. Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
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