Question

p(y)=5y2-3y+7 at y=1,-1
find value

Answer 1

Hey!!

y = 1, - 1

Given polynomial

P( y ) = 5y^2 - 3y + 7

Put y = 1

P ( 1 ) = 5 ( 1 ) ^2 - 3 ( 1 ) + 7

=> 5 - 3 + 7

=> 12 - 3

=> 9


Put y = - 1


P ( - 1 ) = 5 ( - 1 )^2 - 3 ( - 1 ) + 7

=> 5 + 3 + 7

=> 12 + 3

=> 15


Answers :- 9, 15


Hope it helps!

Answer 2

1. P(y) = 5y+2-3y+7

p(1)= 5(1)^2 - 3(1) + 7

p(1)= 5- 3+7

p(1)= 2+7

p(1)= 9

2.

p(-1) = 5(-1)^2 - 3(-1) + 7

p(-1) = 5 + 3 + 7

P(-1)=  8+ 7

p(-1) = 15