Question

P(y) =y^2-y+1 find p (0) ,p(1)and p(2)
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Answer 1

Step-by-step explanation:

Substitute y=2, Therefore, p(0), p(1) and p(2) are 1, 1 and 3 respectively. Find p(0), p(1) and p(2). Therefore, p(0), p(1) and p(2) are 4, 5 and 6 respectively.