Math, asked by kalinishtha3104, 10 months ago

p(y) =y^2-y+1 then p(1) + p(-1)​

Answers

Answered by Hiteshbehera74
4

p(y) =  {y}^{2}  - y + 1  \\ \\ p(1) + p( - 1)  \\ =  {(1)}^{2}  - (1)  + 1 +  {( - 1)}^{2}  - ( - 1) + 1 \\  = 1 - 1 + 1 + 1 + 1 + 1 \\  = 4

Answered by vedant070732
0

Answer:

therefore

answer is 4

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