Math, asked by msaud624, 5 months ago

p (y) = (y + 3) (y - 4), y = -3,4​

Answers

Answered by gopabandhusatpathy
0

Answer:

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Step-by-step explanation:

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Answered by suraj5070
187

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

 \sf \bf p (y) = (y + 3) (y - 4)

 \sf \bf  (i) y=-3 \\ (ii) y=4

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf \huge {(i) y=-3}

 \sf \bf \implies p (y) = (y + 3) (y - 4)

 \sf \bf \implies p (-3) = (-3 + 3) (-3 - 4)

 \sf \bf \implies p(-3) =\cancel {(-3 + 3)} (-7)

 \implies {\boxed {\color{green} {\sf \bf p(-3) =-7}}}

________________________________________

 \sf \bf \huge {(ii) y=4}

 \sf \bf \implies p (y) = (y + 3) (y - 4)

 \sf \bf \implies p (4) = (4 + 3) (4 - 4)

 \sf \bf \implies p(-3) = (7) \cancel {(4-4)}

 \implies {\boxed {\color{green} {\sf \bf p(4) =7}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE\:IT \:HELPS \:YOU}}}

________________________________________

 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \tt {Identities}

 \sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}

 \sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}

 \sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}

 {\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}

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