Question

P (y)=y^4-3y^2+2y+1 at y=1

Answer 1

Step-by-step explanation:

it is given that:

$p(y) = {y}^{4} - 3 {y}^{2} + 2y + 1$

we have to find value of this expression at y=1

$p(1) = {1}^{4} - 3 {(1)}^{2} + 2 \times 1 + 1$

$p(1) = 1 - 3 + 2 + 1$

$p(1) = 1$

PLEASE MARK MY ANSWER AS BRAINLIEST AND THANK ME.