p(y) = y2 – 2√2y + 1, then find the value of p (2√2 )
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Step-by-step explanation:
Given
P(y)=y2−32y+1
P(32)=(33)2−32.(2)21+1
=(2)32−3(21+31)21+1
=232−334×21+1
=232−3.232+1
=−2.232+
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