Math, asked by rehannaqvi2007, 3 days ago

p(y) = y2 – 2√2y + 1, then find the value of p (2√2 )​

Answers

Answered by tiwarisunjyoti
0

Step-by-step explanation:

Given

P(y)=y2−32y+1

P(32)=(33)2−32.(2)21+1

              =(2)32−3(21+31)21+1 

              =232−334×21+1

              =232−3.232+1

              =−2.232+

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