Question

p(y)=y²-y+1 then p(0) ?
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Answer 1

Answer:

as p(y) =y²-y+1

then p(0)=0²-0+1= 1

We have put the value '0' at the place of y

Answer 2

p(y)=y²-y+1

p(0)=0²-0+1

p(0)=1