Question

P(y)=y²-y+1 then value of p(-1) is

Answer 1

Answer:

1

Step-by-step explanation:

Given that,  $P(y)=y^{2}-y+1$

So, $P(y)=1^{2}-(1)+1=1$ .

Answer 2

Answer:

P(-1)=y^2-y+1

P(-1)=(-1)^2-(-1)+1

P(-1)=1+1+1=3

Step-by-step explanation:

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