Question

P(y) = y3 -3√2y+1 find out p(3√2) =?

Answer 1

Answer:

The answer is $50\sqrt 2-17$

Step-by-step explanation:

Given $P(y)=y^3-3\sqrt 2y+1$

Therefore, $P(3\sqrt 2)=(3\sqrt 2)^3-3\sqrt 2(3\sqrt 2)+1$

                               $=3^3\times (\sqrt2)^2\times \sqrt 2-9(\sqrt 2)^2+1\\\\=25\times 2\sqrt 2-9(2)+1\\=50\sqrt 2-18+1\\=50\sqrt 2-17$