Question

p(y)=ysqrt-64y


Find the zeros of the polynomial

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$p(y) = y ^{2} - 64y$

• Is a quadratic equation

so we can write it as follows :-

$y(y - 64)$

let p(y)=0

• so
• $y(y - 64) = 0 \\ \\ y - 64 = \frac{0}{y}$
• $y - 64 = 0$
• $y = + 64$
• Therefore the roots or zeros of the given quadratic equation is either 0 or 64