P (z)=1/2z4+2/3z2+9 is the example which of the polynomial
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biquadratic polynomial
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Thus the result in the example is 9 = 2·4+1. ... For the next example we take p1(z)=4z4 − 64 and p2(z ) = z2 − 4. ... 2z2 +1. We have p(z)=(z −i)2(z +i)2. Thus this polynomial has two different complex roots,.
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