P(Z) = z²-1 at Z = -1
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GIVEN⟹p(z)=z2−1(∵z=−1)
\tt \pink { \implies\: p( - 1) = ( - 1) {}^{2} - 1}⟹p(−1)=(−1)2−1
\tt \purple{ \implies \: p( - 1) = 1 - 1}⟹p(−1)=1−1
\boxed{\tt \green{ \implies \: p( - 1) = 0}}⟹p(−1)=0
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