Math, asked by karthikgurrala12345, 18 hours ago

P(Z) = z²-1 at Z = -1​

Answers

Answered by talpadadilip417
0

Step-by-step explanation:

 \tt \red{ GIVEN :-\implies \: p(z) =  {z}^{2}  - 1 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ( \because \: z =- 1)}

 \tt \pink { \implies\: p( - 1) = ( - 1) {}^{2}  - 1}

 \tt \purple{ \implies \: p( - 1) = 1 - 1}

  \boxed{\tt \green{ \implies \: p( - 1) = 0}}

Answer:

Step-by-step explanation:

hope it help you.

thanks

Answered by Rudragb1324
0

Answer:

GIVEN⟹p(z)=z2−1(∵z=−1)

\tt \pink { \implies\: p( - 1) = ( - 1) {}^{2} - 1}⟹p(−1)=(−1)2−1

\tt \purple{ \implies \: p( - 1) = 1 - 1}⟹p(−1)=1−1

\boxed{\tt \green{ \implies \: p( - 1) = 0}}⟹p(−1)=0

Step-by-step explanation:

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