Question

(p²+1)q - p²- q²
$factorize$
​

Answer 1

Answer:

(p^2-q)(q-1)(p

2

−q)(q−1)

Step-by-step explanation:

\begin{gathered}(p^2+1)q-p^2-q^2\\=p^2q+q-p^2-q^2\\=(p^2q-p^2)+(q-q^2)\\=p^2(q-1)-q(q-1)\\=(p^2-q)(q-1)\end{gathered}

(p

2

+1)q−p

2

−q

2

=p

2

q+q−p

2

−q

2

=(p

2

q−p

2

)+(q−q

2

)

=p

2

(q−1)−q(q−1)

=(p

2

−q)(q−1)