Question

p² - 10xp + 16x² - q² + 6xq
factorize​

Answer 1

Answer:

$(p-5x)^{2} - (3x -q)^{2}$

Step-by-step explanation:

p² - 10xp + 16x² - q² + 6xq

= $p^{2} - 10xp + (25x^{2} - 9x^{2}) -q^{2} + 6xq$

= $p^{2} - 10xp + 25x^{2} - 9x^{2} -q^{2} + 6xq$

• $(a^{2}-b^{2}) = a^{2} - 2ab +b^{2}$

= $(p-5x)^{2} - (9x^{2} +q^{2} - 6xq)$

= $(p-5x)^{2} - (3x -q)^{2}$