Question

p² - 16q² pl factorise this​

Answer 1

Using identity

${x}^{2} - {y}^{2} = {x}^{2} - 2xy + {y}^{2}$

${p}^{2} - {16q}^{2} \\ = {p}^{2} - 2(p)(16q) + {256q}^{2} \\ = {p}^{2} - 32pq + {256q}^{2}$