Question

p²-2p-120 factorise​

Answer 1

Answer:

(p+10)(p−12)

Step-by-step explanation:

The first term is, p2 its coefficient is 1 .

The middle term is, -2p its coefficient is -2 .

The last term, "the constant", is -120

Step-1 : Multiply the coefficient of the first term by the constant 1 • -120 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is -2 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19

-20 + 6 = -14

-15 + 8 = -7

-12 + 10 = -2

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 10

p2 - 12p + 10p - 120

Step-4 : Add up the first 2 terms, pulling out like factors :

p • (p-12)

Add up the last 2 terms, pulling out common factors :

10 • (p-12)

Step-5 : Add up the four terms of step 4 :

(p+10) • (p-12)

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Answer 2

Answer:

(p-12) (p+10)