Question

p²+2p-(q+1)(q-1) factorise it please!​

Answer 1

Step-by-step explanation:

(q+1)(q-1) = q²-1

p²+2p-(q²-1) = p²+2p-q²+1 = p²+2p+1 -q²

Since p²+2p+1 = (p+1)²

p²+2p-(q²-1) = (p+1)²-q²

Considering a =(p+1) and b=q => a²-b²= (a-b)(a+b)

p²+2p-(q²-1) = (p+1)²-q² = (p+1-q)(p+1+q)

After rearranging ,

:.p²+2p-(q²-1) = (p-q+1)(p+q+1)