Question

p²+2p-(q+1)(q-1) factorise it please!


Koi he ​

Answer 1

$\large\green{\textsf{✩ Verified Answer ✓ }}$

Given: p2 + pq + q2/4 + 1 + 2p + q We can rewrite the given equation as = p2 + (q/2)2 + 12 + pq + 2p + q = p2 + (q/2)2 + 12 + 2(p)(q/2) + 2(p)(1) + 2(1)(q/2) = (p + q/2 + 1)2 [ ∵ a2 + b2 + c2 + 2ab + 2bc + 2ca = (a + b + c)2 ]

Answer 2

Answer:

Hello

Explanation:

$\pink{ \Large{\boxed{ \tt{ \blue{αηsωєя : }}}}}$

(q+1)(q-1) = q²-1

p²+2p-(q²-1) = p²+2p-q²+1 = p²+2p+1 -q²

Since p²+2p+1 = (p+1)²

p²+2p-(q²-1) = (p+1)²-q²

Considering a =(p+1) and b=q => a²-b²= (a-b)(a+b)

p²+2p-(q²-1) = (p+1)²-q² = (p+1-q)(p+1+q)

After rearranging ,

:.p²+2p-(q²-1) = (p-q+1)(p+q+1)

Yep