Question

(p²-3q²)²-16(p²-3p²)+63

Answer 1

Hi ,

( p² - 3q² )² - 16( p² - 3q² ) + 63

=(p²-3q²)² - 9(p² - 3q² ) - 7(p²-3q² )+ 63

= (p²-3q²)[p² -3q²-9]-7[p²-3q²- 9]

= [ p² - 3q² - 9 ] ( p² - 3q² - 7 )

I hope this helps you.

:)