p2+4q2=4pq then p:q=?
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Answered by
7
p²+4q²=4pq
p²+4q²-4pq=0
(p-2q)²=0
p-2q=0
p=2q
p/q=2
p:q=2
p²+4q²-4pq=0
(p-2q)²=0
p-2q=0
p=2q
p/q=2
p:q=2
dhaneshwar:
p2
Answered by
4
p^2 + 4q^2 =4pq
p^2 + 4q^2-4pq=0
assume a=p & b=2q
so, it is of the form (a-b)^2 =a^2+b^2-2ab
so the factors of (p-2q)^2 are (p-2q)(p-2q)
therefore (p-2q)=0 => p/q =2/1 similar to p:q =2:1
p^2 + 4q^2-4pq=0
assume a=p & b=2q
so, it is of the form (a-b)^2 =a^2+b^2-2ab
so the factors of (p-2q)^2 are (p-2q)(p-2q)
therefore (p-2q)=0 => p/q =2/1 similar to p:q =2:1
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