Question

p2 - 5p + 6 = 0 is ​

Answer 1

Answer:

p2-5p+6=0

We add all the numbers together, and all the variables

p^2-5p+6=0

a = 1; b = -5; c = +6;

Δ = b2-4ac

Δ = -52-4·1·6

Δ = 1

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

p1=−b−Δ√2ap2=−b+Δ√2a

Δ−−√=1√=1

p1=−b−Δ√2a=−(−5)−12∗1=42=2

p2=−b+Δ√2a=−(−5)+12∗1=62=3

Step-by-step explanation:

Answer 2

Step-by-step explanation:

p^2-6p-p+6

p(p-6)-1(p-6)

(p-1)(p-6)

zeroes are 1,6.