Question

(p²+7p+7)+(p+4)perform the division by algabra division​

Answer 1

Answer:

p^2+7p+7 = (p+4)(p+3) +(-5)

Answer 2

Solution:

p+4 ) p²+7p+7 ) p+3

⠀⠀⠀⠀p²+4p

⠀⠀⠀(-)⠀(-)

⠀⠀____________

⠀⠀⠀⠀⠀⠀3p+7

⠀⠀⠀⠀⠀⠀3p+12

⠀⠀⠀⠀⠀(-)⠀(-)

⠀⠀____________

⠀⠀⠀⠀⠀⠀⠀⠀-5

Quotient= p+3

Remainder=-5

_______________________________

Verification:

Divided=Quotient×Divisor+Remainder

L.H.S.= p²+7p+7

R.H.S.=(p+3)(p+4)-5

⠀⠀⠀⠀=p²+4p+3p+12-5

⠀⠀⠀⠀=p²+7p+7

⠀⠀⠀⠀=L.H.S

Hence, verified.