Question

P2+9p+18
please tell me
in factorisation​

Answer 1

Answer:

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "p2" was replaced by "p^2".

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1 Factoring p2-9p+18

The first term is, p2 its coefficient is 1 .

The middle term is, -9p its coefficient is -9 .

The last term, "the constant", is +18

Step-1 : Multiply the coefficient of the first term by the constant 1 • 18 = 18

Step-2 : Find two factors of 18 whose sum equals the coefficient of the middle term, which is -9 .

-18 + -1 = -19

-9 + -2 = -11

-6 + -3 = -9 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and -3

p2 - 6p - 3p - 18

Step-4 : Add up the first 2 terms, pulling out like factors :

p • (p-6)

Add up the last 2 terms, pulling out common factors :

3 • (p-6)

Step-5 : Add up the four terms of step 4 :

(p-3) • (p-6)

Which is the desired factorization

Equation at the end of step

1

:

(p - 3) • (p - 6) = 0

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Answer 2

Step-by-step explanation:

p^2+9p+18=0 is a quadratic equation

splitting middle term of equation we have,

p^2+6p+3p+18=0

=p(p+6)+3(p+6)=0

(p+6)(p+3)=0

so, p= -6 or -3

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