Math, asked by gopal2871, 8 months ago

p2 +q2=m2 ka solution​

Answers

Answered by sathyamargerate0410
2

Step-by-step explanation:

p²+q²=m²

This is a Pythagorean triplet

Where m=k²+1

(p, q)=(k²-1,2k) or (2k,k²-1)

Answered by sourishsarkarkgec
0

Answer: The required solution with respect to"p" is: p=\sqrt{(m+q)(m-q)}.

Step-by-step explanation:

We assume that p,q,m are co-prime and m be an odd number.

Since m is odd, either p or q must be even since an odd number is always the sum of an odd and an even number.

We can write the equation as:

p^2=m^2-q^2\\= > p=\sqrt{m^2-q^2}\\ = > p=\sqrt{(m+q)(m-q)} .

This is the required solution of the given equation.

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