Question

(p²+q²-r²)²-4p²q²


please help me out in factorizing it......

Answer 1

your ans

given:-

(p2+q2-r2)2-4p2q2

now

this is forming an identity

a2-b2=(a+b)(a-b)

so
here
a=(p2+q2-r2)
b=(2pq)2

so

(p2+q2-r2)2-(2pq)2=(p2+q2-r2+2pq)(p2+q2-r2-2pq)

Answer 2

Answer:

refer the attachment file mate I!☺