Question

(p²+q²+r²)(pq+qr);p=2,q=-3,r=1

Answer 1

Question:-

( p² + q² + r² )(pq + qr )

Where ; p = 2 , q = -3 , r = 1

Solution:-

We have value of p , q and r

So put the value of on equation

=> ( p² + q² + r² )(pq + qr )

We get

=> {( 2 )² + ( - 3 )² + ( 1 )² ) }( 2 × - 3 + - 3 × 1 )

=> ( 4 + 9 + 1 ) ( - 6 + - 3 )

=> ( 4 + 10 ) ( - 9 )

=> ( 14 ) ( - 9 )

=> 14 × - 9

=> - 126

Answer = - 126