(p2+q2+r2)(pq+qr) ; p=2,q=-3,r=1
Answers
Answered by
1
Answer:
Given:(p
2
+q
2
+r
2
)(pq+qr)
Substituting p=2,q=−3 in the above equation, we get
=(2
2
+(−3)
2
+r
2
)(2×−3+(−3)r)
=(4+9+r
2
)(−6−3r)
=−(13+r
2
)(3r+6)
=−(39r+78+3r
3
+6r
2
)
=−(3r
3
+6r
2
+39r+78)
Answered by
2
Answer:
-99
Step-by-step explanation:
Given--p=2,q=-3,r=1
(p2+q2+r2)(pq+qr)
((2)²+(-3)²+(1)²)(2×(-3)+(-3)×1)
(4+6+1)(-6-3)
(11)(-9)
-99
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