Question

p2q-pr2-pq+r2 This is a factorise
​

Answer 1

Answer:

Step-by-step explanation:

p²q−pr²−pq+r²

 

Do the grouping p²q−pr²− pq + r² = (p²q−pr²)+(−pq+r²), and factor out p in the first and −1 in the second group.

p(pq−r²)−(pq−r²)

Factor out common term pq−r² by using distributive property.

(pq−r²)(p−1)

#HOPE IT'S HELP YOU MATE✌

Answer 2

Step-by-step explanation:

$\bf P^2q-Pr^2-Pq+r^2$

$\sf = P^2q-Pq+r^2-Pr^2$

$\sf = Pq(P-1)+r^2(1-P)$

$\sf = Pq(P-1) - r^2(P-1)$

$\bf = (Pq - r^2)(P-1)$

Hope It helps you✌️