Math, asked by alvingcherianm, 5 hours ago

p²x - 2{px – 3х(х2² – За – х²)} ​

Answers

Answered by likhithar6bstdominic
1

Answer:

P2x – 2{px – 3x (x2 – (3a – x2 )}

= p2x – 2{px – 3x (x2 – 3a – x2)}

= p2x – 2{px – 3x (2x2 – 3a)}

= p2x – 2{px – 6x3 + 9ax}

= p2x – 2px + 12x3 – 18ax

Answered by chandrakalakavitha21
2

Answer:

P2x – 2{px – 3x (x2 – (3a – x2 bar))}

= p2x – 2{px – 3x (x2 – 3a – x2)}

= p2x – 2{px – 3x (2x2 – 3a)}

= p2x – 2{px – 6x3 + 9ax}

= p2x – 2px + 12x3 – 18ax

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