p2x2 + c2x2 -- ac2– ap?
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Solution :
Given expression : p2x2+c2x2−ac2−ap2
Here, x2 is common in first two terms and (-a) is common in last two terms.
∴p2x2+c2x2−ac2−ap2=x2(p2+c2)−a(c2+p2)
=x2(p2+c2)−a(p2+c2)=(p2+c2)(x2−a)
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