Question

p²x² + (p²_q²)x - q^2= 0​

Answer 1

{p² - x² + (p²- q²)x-q² =

0P²x² + p²x - q²x - q²

=0P²x(x+1) - q²(x+1)(P²-q²) (x+1)X

= q²÷p², x= -1

p² - x² + (p²- q²)x-q² = 0

P²x² + p²x - q²x - q²=0

P²x(x+1) - q²(x+1)  

(P²-q²) (x+1)

X= q²÷p², x= -1

Answer 2

Answer:

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