Question

p2x2+(p2-q2)x-q2=0 find x by quadratic formula ​

Answer 1

Answer:

x = -1 or q²/p²

Step-by-step explanation:

x = -b±√(b² - 4ac) / 2a

a = p², b = p² - q², c = - q²

x = -(p² - q²)±√[(p² - q²)² - 4p²(-q²) / 2p²

  = -(p² - q²)±√(p⁴ + q⁴ - 2p²q²+4p²q²) / 2p²

  = -(p² - q²) ± √(p²+q²)²/2p²

  = -(p² - q²) ± (p²+q²)/2p²

So x can be -(p² - q²) + (p²+q²)/2p² | or -(p² - q²) - (p²+q²)/2p²

 = -p² + q² +p²+q²/2p²                     |  = -p²+q²-p²-q²/2p²

  = q²/p²                                           |   = -2p²/2p²

                                                         |    = -1