Question

p²x²+(p²-q²)x-q²=0 solve with quadratic formula

Answer 1

Answer:

P^2x^2+p^2x-q^2x-q^2=0

P^2x(x+1)-q^2(x+1)=0

(P^2x-q^2)(x+1)=0

X=q^2/p^2,x=-1

Answer 2

Answer:

The value of x is q²/p² , -1

Step-by-step explanation:

p²x² + (p² - q²)x - q² = 0

p²x² + p²x - q²x - q² = 0

p²x(x + 1) - q²(x + 1) = 0

(p²x - q²) (x + 1) = 0

(p²x - q²) = 0

p²x = q²

x = q²/p²

x + 1 = 0

x = -1

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Hope it helps!