p3-27 find the equation
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Answer:
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 27 is the cube of 3
Check : p3 is the cube of p1
Factorization is :
(p - 3) • (p2 + 3p + 9)
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