Math, asked by nayeem28, 7 months ago

p3-3p2+2-6-pq+3q factorise

Answers

Answered by aryan073

1

Step-by-step explanation:

p³-3p²+2-6-pq+3q

p³-3p²-4-pq+3q

p³-3p²-pq+3q-4=0

p²(p-3)-q(p-3)-4=0

p=3

p²-q-4=0

p²-2p+2p-4=0

p=2

p=-1

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