Question

p³(q-r)³+q³(r-p)³+(p-q)³​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

=[p(q-r)]³+[q(r-p)]³+[r(p-q)]³

If (a+b+c) = 0, then a³+b³+c³= 3ab

Here, q(r-p)+ p(q-r)+ r(p-q)=0

=> p³(q-r)³+ q³(r-p)³+ r³(p-q)³= 3[p(q-r)×q(r-p) ×r(p-q)]

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