Question

p3+q3-r3-3pqr if (p=4,q=-3,r=2)
please solve the question​

Answer 1

Answer:

p³+q³-r³-3pqqr=101

Step-by-step explanation:

p³+q³-r³-3pqr

=>4³+(-3)³-2³-3×4×(-3)×2

=>64-27-8+72

=>64+72-27-8

=>136-35

•°•101

hope it helps you

Thanks

Answer 2

The answer is 101

• p^3+q^3-r^3-3pqr
• (4)^3+(-3)^3-(2)^3-{3*4*(-3)*2}
• 64+(-27)-8-{-72}
• 64-27-8+72
• 64-27+64
• 101

Hope it helps youu.......