Question

(p³q6-p6q³)÷p³q³ please solve that​

Answer 1

is it correct...........................?

Answer 2

Answer:

(p^3q^6-p^6q^3)÷p^3q^3

=p^3q^6-p^6q^3=(p^3q^3×q^3)-(p^3q^3×p^3)

taking p^3q^3(q^3-p^3)

dividing

p^3q^6-p^6q^3/p^3q^3=p^3q^3(q^3-p^3)[as a^m/a^n=a^m-a^n]

=q^3-p^3.

hope it helps you:)

☆thank you☆